A1500 kg car travels at 90 km/h east and collides with a 1000 kg car traveling at 60 km/h north. the two cars stick together after the collision. the road surface conditions were wet such that us= 0.5 and uk = 0.4. what is the speed of the cars, in m/s, immediately after the collision? what is the direction of the velocity of the cars immediately after collision? how far did the two vehicles skid, in meters, after the collision?

direction =

velocity =

distance skid = 145.2 meters

Explanation:

Let the mass of the car 1 m1 = 1500 kg, m2 = 1000 kg, v1 = 90 km/h and v2 = 60 km/h.

v1 = 90 i and v2 = 60 j.

applying conservation of linear momentum in i and j direction since there is no external force involved.

along i direction:

          1

along j direction:

         2

where v is the new velocity of combined car and Ф is the angle made with x axis.

equation 2÷1

therefore \tan \Phi = \frac{4}{9}

therefore the direction is

and velocity will be

the car will skid until the total energy of the car is dissipiated by friction

therefore

substituting the values we get x = 145.2 meters

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