You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves down a frictionless track to a height of 3.00 m.

how fast are you moving when you arrive at the 3.00-m height? - 22.1 m/s
- 20.8 m/s
- 23.4 m/s
- 14.7 m/s

To solve this problem, we need to use both energy conservation and potential kinetic equations.

When the energy accumulated from a certain height is released, it becomes 'motion' energy or kinetic energy. Mathematically this can be expressed as

PE = KE

Where

m = mass

g = Gravitational acceleration

v = Velocity

Change of the height

We know that the body, based on a reference system where the floor is the zero coordinate, starts from being 25 meters high to fall to 3 meters high, so the total difference in height would be

We also have to

Using the previous equation we have to:

Replacing

The correct answer is 20.8m/s

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6