Astone is thrown straight down from the edge of a roof, 1200 ft above the ground, at a speed of 9 ft/sec. a. given that the acceleration due to gravity is -32 ft/sec2, how high is the stone 2 seconds later?

Answer, d' = 1118 meters

Explanation:

Given that,

The stone is thrown straight down from the edge of a roof, h = 1200 ft

Speed of the stone, u = 9 ft/s

The acceleration due to gravity is,

Time, t = 2 s

Let d is height reached by the stone in 2 seconds. It can be calculated using second equation of motion as :

Here, a = g

d = 82 m

So, the height of stone after 2 seconds is,

d' = 1200 - 82

d' = 1118 meters

Hence, this is the required solution.

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