The refueling planes were able to air-transfer a total of 687 gallons of fuel to the plane in 9 refueling transfers. assume that the refueling nozzle had a diameter of 1.45 inches and each refueling took 2.41 minutes to perform. calculate the velocity of the fuel through the nozzle. assume that the fuel filled the entire cross-sectional area of the nozzle.

the velocity of the fuel through the nozzle v= 6.45 ft/s

Explanation:

Given values

Volume =  687 gallons=

9 refueling transfers

dia of nozzle d= 1.45 inches

each refueling took 2.41 minutes to perform. t= 2.41×60×9= 1247.4 sec

Volume of fuel pumped in time t is give by

V= Avt

A= area of mouth of pipe

v= flow rate

t= time

A= πr^2

A=

now substituting the values in equation 1 we get

v= 1.966 m/sec

v= 6.45 ft/s

the velocity of the fuel through the nozzle v= 6.45 ft/s

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

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it may be wrong but i think its a