Monochromatic light of wavelength 385 nm is incident on a narrow slit. on a screen 3.00 m away, the distance between the second diffraction minimum and the central maximum is 1.40 cm. (a) calculate the angle of diffraction θ of the second minimum.(b) find the width of the slit.

To solve this problem it is necessary to apply the concepts related to the concept of overlap and constructive interference.

For this purpose we have that the constructive interference in waves can be expressed under the function

Where

a = Width of the slit

d = Distance of slit to screen

m = Number of order which represent the number of repetition of the spectrum

Angle between incident rays and scatter planes

At the same time the distance on the screen from the central point, would be

Where y = Represents the distance on the screen from the central point

PART A ) From the previous equation if we arrange to find the angle we have that

PART B) Equation both equations we have

Re-arrange to find a,

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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