Amass of 0.26 kg on the end of a spring oscillates with a period of 0.45 s and an amplitude of 0.15 m .a) find the velocity when it passes the equilibrium point. b) find the total energy of the system. c) find the spring constant. d) find the maximum acceleration of the mass.

a)V= 2.09 m/s

b)TE= 0.56 J

c)K=50.47 N/m

d)a=29.23 m/s²

Explanation:

Given that

m = 0.26 kg  ,  T= 0.45 s  ,A= 0.15 m

We know that time period given as

ω =Angular frequency

ω = 13.96 rad/s

The velocity at equilibrium

V=  ω A

V= 13.96 x 0.15

V= 2.09 m/s

The total energy TE

TE= 0.56 J

The spring constant K

Maximum stored energy in the spring

From energy balance

U= TE

K A² = m V²

K=50.47 N/m

The maximum acceleration a

a= ω² A

a = 13.96²  x 0.15 m/s²

a=29.23 m/s²

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.