Frieda stands on a hill with a slope of 12°. if her mass is 65 kg, what is the
magnitude of the normal force acting on her?

Normal force on Frieda is 623.71N

Explanation:

Given that Frieda stands on a hill with a slope of 12°

Let mass of Frieda is m=65kg

θ is slope of hill = 12°

Figure show that free body diagram of Frieda standing on hill if slope 12°

From free body diagram,

Normal force = mgcosθ

                      = (65)(9.81)(cos12)

                      = (65)(9.81)(0.9781)

                      = 623.71N

Thus, normal force on Frieda is 623.71N

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what are the options.

explanation: