Abowling ball of mass 7.9 kg moves in a straight line at 1.55 m/s. how fast must a ping-pong ball of mass 1.416 g move in a straight line so that the two balls have the same momentum? answer in units of m/s.

8.647 m/s

Explanation:

Momentum of a particle of mass m moving with a velocity v is given by the formula:-

p = mv

For bowling ball m = 7.9 Kg  , v = 1.55 m/s

So, momentum is given by = (7.9)×(1.55)

                                                                                             = 12.245 kg-m/s -(1)

Now, let velocity of the ping pong ball be v m/s .

Mass of ping pong ball = 1.416 kg

So, momentum of the ball is given by

= 1.416v kg-m/s

According to the question ,  =

Thus, 1.416v = 12.245

v = 8.647 m/s

so, Required velocity of ping pong ball is 8.647 m/s.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards