Asmall artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. if the pressure drop across the artery is 1.15 kpa, what is the flow rate through the artery? assume that the temperature is 37°c and the viscosity of whole blood is 2.084 × 10-3 pa·s.

Explanation:

P = Pressure difference = 1.15 kPa

r = Radius =

= Viscosity of liquid =

l = Length of artery =

From Poiseuille's equation we have

The flow rate of blood is

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz