Aparticle with charge q = 10-9 c and mass m = 5.0 x 10-9 kg is moving in a magnetic field whose magnitude is 0.003 t. the speed of the particle is 500 m/s and its velocity vector makes an angle of 45 with the magnetic field vector. what is the magnitude of the acceleration of the particle?

a=0.212 m/s²

Explanation:

Given that

q= 10⁻⁹ C

m = 5 x 10⁻⁹ kg

Magnetic filed ,B= 0.003 T

Speed ,V= 500 m/s

θ= 45°

Lets take acceleration of the mass is a m/s²

The force on the charge due to magnetic filed B

F= q V B sinθ

Also F= m a  ( from Newton's law)

By balancing these above two forces

m a= q V B sinθ

a=0.212 m/s²

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

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