What is the chance of a light car safely rounding an unbanked. curve on an icy road as compared to that of a heavy car: worse, the same, or better? assume that both cars have the same speed and are equipped with identical tires. account for your answer.

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Both cars will move in the Same way

Explanation:

Moving on an unbanked icy road, the cars will have friction which will keep them from slipping on the icy road. This friction here is called Centripetal Force. The friction force due to which the tires roll and do not slip is the static friction μsN, (μs= coefficient of static friction , N= Normal Force which is equal to the weight of the car/body, so N=mg).

Now from above description, the centripetal force( ) becomes,

                          =f=μsN         ,       (N=mg)

so ,                     =μs(mg)

As we know the formula of centripetal force is

                        = m /r

Putting the value of  from above

                        μs(mg) = m /r

cutting the 'm' from both sides, we get

                        μs(g) = /r

                        μs = /rg

we see from the derivation that there is no effect of mass on the cars, so in case of both cars having same speed and same tires, they will act in the same way resulting no effect of their masses on them

c

explanation:

need to see circuit to get time constant