A1,492.3-kg airplane travels down the runway. each of its four engines provides a force of
1,447.5 n. find the acceleration of the airplane, in m/s2. (ignore friction.)

The acceleration of the plane is, a = 3.88 m/s²

Explanation:

Given data,

The mass of the airplane, m = 1492.3 kg

The force produced by each engine, f = 1447.5 N

Therefore, the total force produced by four engines, F = 5790 N

The force acting on an object is equal to the product of its mass and acceleration,

                                       F = ma

Therefore, the acceleration is

                                       a = F/m

Substituting the given values in the above equation,

                                       a = 5790 N / 1492.3 kg

                                       a = 3.88 m/s²

Hence, the acceleration of the plane is, a = 3.88 m/s²

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.