Organ pipe a, with both ends open, has a fundamental frequency of 350 hz. the third harmonic of organ pipe b, with one end open, has the same frequency as the second harmonic of pipe a. how long are (a) pipe a and (b) pipe b? (take the speed of sound to be 343 m/s.)

(a) how long is pipe a?
m
(b) how long is pipe b?
m

0.49 m

0.3675 m

Explanation:

f = Frequency

L = Length

The fundamental length is given by

The second harmonic is has

The length of pipe A is 0.49 m

Frequency is given by

For third harmonic n = 3

The length of pipe B is 0.3675 m

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

overcharge is the right answer system