A17-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 24 n. starting from rest, the sled attains a speed of 2.5 m/s in 9.4 m. find the coefficient of kinetic friction between the runners of the sled and the snow.

The coefficient friction

μ = 0.11

Explanation:

To find the coefficient of kinetic can be find using conserved energy equations and knowing the friction force is

fk = μ * N

Now to determine use the equation

Wf = ¹/₂ * m * v² = ¹/₂ * 17 kg * 2.5² m / s = 53.125 J

We = 24.0 N * cos (0) * 9.4 m = 225.6 J

Wt = Wf - We = 53.125 J - 225.6 J = - 172.475 J

Wt = fk * d

fk = Wt / d = 18.35 N

Now to find the coefficient μ'

N = m * g = 17 kg * 9.8  m/s² = 166.6 N

μ = fk / N

μ =  18.35 N / 166.6 N

μ = 0.11

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

the correct choice is a .

do not post any more test or exam questions on