Aproton and an electron are located 12 nm apart. calculate the force of attraction between them?

The force between them is, F = 8.33 x 10⁻¹¹ N

Explanation:

Given data,

The distance between the proton and electron, x = 12 nm

                                                                                   = 12 x 10⁻⁹ m

The electrostatic force between them is given by the formula,

Where k = 9 x 10⁹ Nm²C⁻²

Substituting the given values,

                                    F = 8.33 x 10⁻¹¹ N  

Hence, the force between them is, F = 8.33 x 10⁻¹¹ N                                          

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.

okay i have so many questions. but the big one here is: um wt..f is this mess? ?