Ameteoroid passes through a position in space where its speed is very small relative to earth's and it is at a perpendicular distance of 19 earth radii above earth's surface. the meteoroid is moving in such a way that earth captures it.

what is the speed of the meteoroid when it is one earth radius above the ground

Explanation:

If we call 1 the position in space where the meteoroid of mass m speed is very small relative to Earth's (whose mass is and radius is ) and it is at a perpendicular distance of above Earth's surface, and 2 the position when it is above the ground, then, since in this case mechanical energy is conserved, we can write:

which means:

where K is the kinetic energy and U the gravitational potential energy. Since we can write:

which means:

And since (the distance of an object to the center of the Earth is Earth's radius plus the height of the object), we have:

This for our values is: