Aglider with mass m = 0.230 kg sits on a frictionless horizontal air track, connected to a spring with force constant k = 4.50 n/m . you pull on the glider, stretching the spring 0.130 m , and then release it with no initial velocity. the glider begins to move back toward its equilibrium position (x=0). what is the speed of the glider when it returns to x=0?

what must the initial displacement of the glider be if its maximum speed in the subsequent motion is to be 3.00 m/s?

Answer

given,

mass of glider = 0.23 Kg

spring constant = k = 4.50 N/m

spring stretched to 0.130 m

The springs potential energy =

        U = 0.038 J

at x = 0,the only energy will be kinetic .

         v² = 0.3304

         v = 0.575 m/s

displacement of the glider

      using conservation of energy

        x = 0.678 m

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1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//