Calculate the number of molecules in a deep breath of air whose volume is 2.35 l at body temperature, 37 ∘c, and a pressure of 735 torr. express the answer in molecules to three significant figures. nn = nothing molecules request answer part b the adult blue whale has a lung capacity of 5.0×103 l. calculate the mass of air (assume an average molar mass 28.98 g/mol) contained in an adult blue whale’s lungs at 0.5 ∘c and 1.07 atm, assuming the air behaves ideally. express the answer in kilograms to two significant figures. mm = nothing kg

Part A. 5.36x10²³ molecules of air

Part B. 6.9kg  

Explanation:

Part A.

To calculate the number of molecules of the air we need first find the number of moles of air using the equation of ideal gas law:

   (1)

where P: is the pressure, V: is the volume, n: is the number of moles of the gas, R: is the gas constant and T: is the temperature

Now by using the Avogadro's number we can find the number of molecules of air:

Part B.

Similarly, to calculate the mass of air first we need to detemine the number of moles using equation (1):

So, the mass of air is:

where M: is the average molar mass of air

I hope it helps you!