Aheavy object is dropped from a vertical height of 8.0 m. what is it’s spend when it hits the ground ?

Final speed of the ball = Vf= 12.52 m/s when it hits the ground

Explanation:

Height = S= 8.0 m

Initial Velocity= Vi = 0 m/s

Final Velocity= Vf =?

Acceleration due to gravity= a=9.8m/s²

Using Newtons third equation of motion

2as= Vf²- Vi²

2(9.8) 8= Vf²- 0

156.8= Vf²

Vf=√156.8= 12.52m/s

Final Speed of the ball is 12.52 m/s

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