An engineer has an odd-shaped 13.5 kg object and needs to find its rotational inertia about an axis through its center of mass. the object is supported on a wire stretched along the desired axis. the wire has a torsion constant κ = 0.618 n·m. if this torsion pendulum oscillates through 28 cycles in 58.1 s, what is the rotational inertia of the object?

I = 0.0674 kg.m²

Explanation:

given,

mass = 13.5 Kg

torsion constant = k = 0.618 N.m

number of cycle = 28

time = 58.1 s

Time of one cycle

we know,

      I = 0.0674 kg.m²

the rotational inertia of the object is equal to  I = 0.0674 kg.m²

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever