Steam at 100°c is condensed into a 38.0 g aluminum calorimeter cup containing 280 g of water at 25.0°c. determine the amount of steam (in g) needed for the system to reach a final temperature of 40.0°c. the specific heat of aluminum is 900 j/(kg · °c).

7.2g

Explanation:

From the expression of latent heat of steam, we have

Heat supplied by steam = Heat gain water + Heat gain by calorimeter

mathematically,

+ = +

L=specific latent heat of water(steam)=2268J/g

=specific heat capacity=4.2J/gK

=specific heat capacity of calorimeter =0.9J/gk

=280g

=38g

α=change in temperature

=(40-25)=15

=(40-25)=15

=(100-40)=60

Note: the temperature of the calorimeter is the temperature of it content.

From the equation, we can make the subject of formula

Hence

Hence the amount of steam needed is 7.2g

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