Asinusoidally oscillating current i ( t ) with an amplitude of 4.55 a and a frequency of 879 cycles per second is carried by a long, straight wire. a rectangular loop of copper wire with dimensions b = 45.2 cm by c = 20.3 cm is located a = 50.2 cm from the straight wire, and is coplanar with it. calculate the average power p avg dissipated by the loop if its resistance is 84.3 ω .

The average power is

Explanation:

Given that,

A sinusoidal oscillating current I ( t ) with an amplitude of 4.55 A .

Frequency = 879 cycles

Side b = 45.2 cm

Side c=20.3 cm

Side a = 50.2 cm

Resistance = 84.3 Ω

We need to calculate the angular frequency

Using formula of angular frequency

Put the value into the formula

We need to write the sinusoidal equation

We need to calculate the magnetic flux

Using formula of flux

We need to calculate the induced emf

Using formula of induced emf

Put the value into the formula

We need to calculate the average power

Using formula of average power

Put the value into the formula

Hence, The average power is

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.