Physics, 19.12.2019 04:31 magicpuppydance
Point charges q1=+2.00μc and q2=−2.00μc are placed at adjacent corners of a square for which the length of each side is 5.00 cm. point a is at the center of the square, and point b is at the empty corner closest to q2. take the electric potential to be zero at a distance far from both charges.(1)what is the electric potential at point a due to q1 and q2?
(2)what is the electric potential at point b?
(3)a point charge q3 = -2.00 μc moves from point a to point b. how much work is done on q3 by the electric forces exerted by q1 and q2?
Answers: 1
![V_b = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.05\sqrt2} + \frac{1}{4\pi\epsilon_0}\frac{-2\times10^{-6}}{0.05}\\V_b = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.05} (\frac{1}{\sqrt2}-1)\\V_b = \frac{1}{4\pi\epsilon_0} (4\times 10^{-5})(-0.29)\\V_b = (-\frac{2.9\times10^{-6}}{\pi\epsilon_0})[tex]3) The work done on q3 by q1 and q2 is equal to the difference between energies. This is the work-energy theorem. So,[tex]W = U_b - U_a](/tpl/images/0425/4469/39a18.png)
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Point charges q1=+2.00μc and q2=−2.00μc are placed at adjacent corners of a square for which the len...
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