Starting with an initial speed of 4.54 m/s at a height of 0.337 m, a 2.03-kg ball swings downward and strikes a 4.97-kg ball that is at rest, as the drawing shows.
(a) using the principle of conservation of mechanical energy, find the speed of the 2.03-kg ball just before impact.
(b) assuming that the collision is elastic, find the velocity (magnitude and direction) of the 2.03-kg ball just after the collision.
(c) assuming that the collision is elastic, find the velocity (magnitude and direction) of the 4.97-kg ball just after the collision.
(d) how high does the 2.03-kg ball swing after the collision, ignoring air resistance

a) 5.2170 m/s

b) 2.1911 m/s, to the left

c) 3.0259 m/s, to the right

d) 0.2449 m

Explanation:

Given parameters:

a) Here, the conservation of energy principle can be used.

where

So,

b) Here, the conservation of momentum principle can be used.

Here, our new will be   found in part (a).

(-) sign means that the 2.03 kg ball after collision will bounce back in the left direction.

c) Here, we can use the conservation of momentum principle again.

. Here, will be   found in part (a) again.

(+) sign means that the 4.97 kg ball after collision will swing to the right direction.

d) Here, we can use the conservation of energy principle again.

where and

So,

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

their crystal patterns have been disrupted by stress