Abox of mass 17.6 kg with an initial velocity of 2.25 m/s slides down a plane, inclined at 19◦ with respect to the horizontal. the coefficient of kinetic friction is 0.48. the box stops after sliding a distance x. 17.6 kg µk = 0.48 2.25 m/s 19◦

how far does the box slide? the acceleration due to gravity is 9.8 m/s 2 . the positive x-direction is down the plane. answer in units of m.

2.01 m

Explanation:

Given parameters:

Mass, m = 17.6 kg

Velocity, v = 2.25 m/s

Degree = 19°

Coefficient of kinetic friction, = 0.48

To find the distance, we need to use Work-Energy principle.

So, total energy must be equal to the work done by friction. Here total energy is sum of the initial kinetic energy and the loss in potential energy.

So,

m

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.