Abullet of mass m is fired at speed v0 into a wooden block of mass m. the bullet instantaneously comes to rest in the block. the block with the embedded bullet slides along a horizontal surface with a coefficient of kinetic friction μ. write an expression for how far the block slides (s) in terms of m, m, vo , μ, and g.

Explanation:

mass of bullet = m

mass of block = M

initial speed of bullet = vo

coefficient of friction = μ

Let the horizontal distance traveled before stopping is s.

Let v be the velocity of the bullet and block system after collision.

Use conservation of momentum

m x vo = (M+m) x v

Now use third equation of motion

v² = u² - 2 a s

So,

ingenuity says that the answer is 2.7 m.