In one cycle a heat engine absorbs 450 j from a high-temperature reservoir and expels 290 j to a low-temperature reservoir. if the efficiency of this engine is 55% of the efficiency of a carnot engine, what is the ratio of the low temperature to the high temperature in the carnot engine?

So the ratio will be

Explanation:

We have given heat engine absorbs 450 joule from high temperature reservoir

So

As the heat engine expels 290 j

So work done W = 290 J

We know that efficiency

It is given that efficiency of the engine only 55 % of Carnot engine

So efficiency of Carnot engine

Efficiency of Carnot engine is

0.64

Explanation:

QH = 450 J

Qc = 290 J

efficiency, η = 55 %

Let Tc be the low temperature and TH be the high temperature.

According to the Carnot's theorem

So, the ratio is 0.64.

they start with the same

adding a(n) to an electric circuit would increase the magnetic field around a wire;

b. solenoid

a solenoid is a type of electromagnet whose purpose is to generate a controlled magnetic field.

if the purpose of the solenoid is instead to impede changes in the electric current, a solenoid can be more specifically classified as an inductor rather than an electromagnet.