Consider six proposed properties of electromagnetic radiation: wave speeds of 3.00×108 km/s3.00×108 km/s and 3.00×108m/s3.00×108m/s , wavelengths of 673 nm673 nm and 0.221 nm0.221 nm , and frequencies of 2.39×1018 hz2.39×1018 hz and 4.85×1014 hz4.85×1014 hz . place these according to whether they apply only to the x-ray band, only to the visible light band, to both bands, or to neither band. x-ray band only visible light band only both bands neither band wavelength of 0.221 nm0.221 nm frequency of 2.39×1018 hz2.39×1018 hz speed of 3.00×108 m/s3.00×108 m/s wavelength of 673 nm673 nm frequency of 4.85×1014 hz4.85×1014 hz speed of 3.00×108 km/s3.00×108 km/s answer bank

1) Speed of light (c)       visible, X-rays

2) λ = 0.221 nm                         X-rays

3) λ = 673 nm               Visible

4) .f = 2.39 10¹⁸ Hz                   X-rays

5) .f = 4.85 10¹⁴ Hz        Visible

Explanation:

Electromagnetic radiation has several characteristics

The speed of the wave regardless of its wavelength or frequency is

        c = 3 10⁸ m / s²

There is a relationship with speed

       c = λ f

The speed c is for all waves (x-rays, visible)

Visible light has a wavelength between 400 nm to 700 nm,

X-ray light corresponds to wavelengths less than 10 nm

Light gamma rays for wavelength less than 0.1 nm

Let's look for the frequencies for the two ranges

Visible

      f = c /λ

       f = 3 10⁸/400 10⁻⁹ = 7.5 10¹⁴ Hz

       f = 3 10⁸ (/ 700 10⁻⁹ = 4.29 10¹⁴ Hz

Visible range of the order of 10¹⁴ Hz

X-rays

       f = 3 10⁸/10 10⁻⁹ = 3 10¹⁶ Hz

       f = 3 10⁸ / 0.1 10⁻⁹ = 3 10¹⁸ Hz

X-ray higher frequency 10¹⁶ Hz

1) Speed of light (c)       visible, X-rays

2) λ = 0.221 nm                         X-rays

3) λ = 673 nm               Visible

4) .f = 2.39 10¹⁸ Hz                   X-rays

5) .f = 4.85 10¹⁴ Hz        Visible

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explanation:

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2