Physics, 21.12.2019 09:31 selenaK9514

a round asteroid has a surface gravity of 0.0288 m/s^s. if the mass of the asteroid is 1.10 x 10^18 kg, what is the radius?

a round asteroid has a surface gravity of 0.0288 m/s^s. if the mass of the asteroid is

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air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

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Ireally just need to get finished with precal! i’m really sorry i have to do this! hope this !

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Answer (d) the universe had cooled enough for atoms to combine, protons and neutrons were too far apart to form nuclei;

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The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: $k= \frac{1}{2}mv^2$ where m is the mass of the arrow and v its velocity. all the other options, instead, do not increase the kinetic energy of the system: - pulling farther back on the string : this will just increase the elastic potential energy of the system- holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)- decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)

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a round asteroid has a surface gravity of 0.0288 m/s^s. if the mass of the asteroid is 1.10 x 10^18...

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