An object with a mass of 5.5 kg is allowed to slide from rest down an inclined plane. the plane makes an angle of 30º with the horizontal and is 72 m long. the coefficient of friction between the plane and the object is 0.35. the speed of the object at the bottom of the plane is

Velocity at the bottom will be 16.66 m/sec

Explanation:

We have given mass of the object m = 5.5 kg

Angle which is made by the plane

Distance traveled s = 72 m

Acceleration will be equal to

Initial velocity u = 0 m /sec

We have to find the velocity at the bottom of the plane, that is final velocity v

From third equation of motion we know that

So

v = 16.66 m/sec

nah.   i'm just sleepy.