Amass of 0.54 kg attached to a vertical spring stretches the spring 36 cm from its original equilibrium position. the acceleration of gravity is 9.81 m/s^2.
what is the spring constant? answer in units of n/m.

Explanation:

We have for a spring

            Force =  Spring constant x Elongation

            F = kx

Here force is weight of mass

           F = W = mg = 0.54 x 9.81 = 5.3 N

Elongation, x  = 36 cm = 0.36 m

Substituting

           F = kx

           5.3 = k x 0.36

             k = 14.72 N/m

Spring constant is 14.72 N/m

b

explanation:

bc its just b