Objects with masses of 191 kg and 572 kg are separated by 0.406 m. a 50 kg mass is placed midway between them. 0.406 m b b 191 kg 50 kg 572 kg find the magnitude of the net gravitational force exerted by the two larger masses on the 50 kg mass. the value of the universal gravitational constant is 6.672 × 10−11 n · m2 /kg2 . answer in units of n.

3.06 x 10^{-5} N

Explanation:

mass M1 = 191 kg

mass M2 = 572 kg

mass M3 = 50 kg

distance apart (d) = 0.406 m

gravitational constant (G) = 6.62 x 10^{-11} m^{2}/kg^{2}

Find the magnitude of the net gravitational force exerted by the two larger masses on the 50 kg mas

the net  gravitational force acting on the 50 kg mass (M3) = gravitational force exerted by the larger mass (M2) - gravitational force exerted by the smaller mass (M1)

⇒

net force =

net force =

net force =  

net force = 3.06 x 10^{-5} N

he kicked it 10 feet straight up into the air? i think this works.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.