Adiatomic molecule is rotating about its center of mass with an angular speed of 2.50 ✕ 1012 rad/s. determine the rotational kinetic energy (in j) of one molecule, if the gas is fluorine which has a bond length of 0.919 å and a molecular molar mass of 38.0 g/mole.

kinetic energy Ke = 4.16 × 10^-22J

Explanation:

Moment of inertia I = 2mr^2

m = ( 38 × 10^-3 kg/mol)/(2× 6.02× 10^23)

Atomic mass m= 3.16 × 10^-26 kg

r = bond length/2 = 0.919Å/2 = 0.4595Å

Bond radius r = 0.4595 × 10^-10m

I = 2 × 3.16×10^-26 × (0.4595 × 10^-10)^2

I = 1.33 × 10^-46 kgm^2

Kinetic energy Ke = 1/2 (I× w^2)

Angular speed w = 2.50 ✕ 10^12 rad/s

Ke = 1/2( 1.33 × 10^-46 kgm^2 × ( 2.5 × 10^ 12rad/s)^2)

Ke = 4.16 × 10^-22J

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.