The hubble space telescope orbits the earth at an approximate altitude of 612 km. its mass is 11,100 kg and the mass of the earth is 5.97×1024 kg. the earth's average radius is 6.38×106 m. what is the magnitude of the gravitational force that the earth exerts on the hubble?

magnitude of the gravitational force is 9.04 × N

Explanation:

given data

altitude = A = 612 km = 612000 m

mass M = 11,100 kg

mass of the Earth m = 5.97 × kg

Earth average radius = 6.38 ×  m

to find out

magnitude of the gravitational force

solution

first we get here distance from space to centre of earth that is

distance = altitude + earth radius

distance = 612000  +  6.38 ×  m

distance = 6.99 ×  m  

so now we get here  magnitude of the gravitational force that is express as

magnitude of the gravitational force F =   ...........1

here G is gravitational constant  that is 6.67 × Nm² /kg and M is mass of space and m is mass of earth

put here all value we get

F =

F =

F = 9.04 × N

so magnitude of the gravitational force is 9.04 × N

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

not too sure thinking all accelerations are pointed down