Two coils are wound around the same cylindrical form. when the current in the first coil is decreasing at a rate of -0.245 a/s , the induced emf in the second coil has a magnitude of 1.60×10−3 v .part apart completewhat is the mutual inductance of the pair of coils? mm= 6.53×10−3 hprevious answerscorrectpart bpart completeif the second coil has 20 turns, what is the flux through each turn when the current in the first coil equals 1.25 a ? φφ= 4.08×10−4 wbprevious answerscorrect

Complete question:

c.If the current in the second coil increases at a rate of 0.365 A/s , what is the magnitude of the induced emf in the first coil?

a.

b.flux through each turn = Ф =

c.magnitude of the induced emf in the first coil = e=

Explanation:

a. rate of current changing = " alt="M=\frac{1.60\times10^{-3} V}{0.240\frac{A}{s} }}" />" />

  Induced emf in the coil =e=

  For mutual inductance in which change in flux in one coil induces emf in the second coil given by the farmula based on farady law

b.

  Flux through each turn=?

  Current in the first coil =1.25 A

   Number of turns = 20

       using   MI = NФ

     flux through each turn = Ф =  

   flux through each turn = Ф =

c.

   second coil increase at a rate = 0.365 A/s

  magnitude of the induced emf in the first coil =?

 using  

magnitude of the induced emf in the first coil = e=

0.19 m/s and 0.45 m/s