The rotating arm starts from rest and acquires a rotational speed n = 600 rev/min in 2 seconds with constant angular acceleration. find the time t after starting before the acceleration vector of end p makes an angle of 45 with the arm op

The time after starting is 0.178 sec.

Explanation:

Given that,

Rotational speed = 600 rev/min

Time t = 2 sec

Angle = 45

Distance OP= 6''

According to figure,

We need to calculate the angular acceleration

Using formula of angular acceleration

Put the value into the formula

We need to calculate the tangential acceleration

Using formula of tangential acceleration

Put the value into the formula

We need to calculate the normal acceleration

Using formula of normal acceleration

For angle

Put the value into the formula

We need to calculate the time

Using the kinematics equation

Put the value into the formula

Hence, The time after starting is 0.178 sec.

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement