You have a 200−ω resistor, a 0.400-h inductor, and a 6.00−μf capacitor. suppose you take the resistor and inductor and make a series circuit with a voltage source that has voltage amplitude 30.0 v and an angular frequency of 250 rad/s.

(a) what is the impedance of the circuit?

(b) what is the current amplitude?

(c) what are the voltage amplitudes across the resistor and across the inductor?

(d) what is the phase angle φ of the source voltage with respect to the current? does the source voltage lag or lead the current?

(e) construct the phasor diagram.

a.223.6Ω

b.0.134A

c. , [text]V_{L}= 13.4V[/tex]

d.63.43, the voltage lead the current

e. see attachment

Explanation:

the diagram can be shown in the attached document.

We can write the voltage as a function of time

where V= amplitude of the voltage

            w=angular frequency.

from the question we have V=30v and w=250rad/s

hence we can rewrite the voltage as  

a.the impedance of the circuit is express as

Where R=200Ω and XL=wL= 250*0.400=100Ω

Hence

Ω

b. The current amplitude is the ratio of the voltage amplitude to the circuit impedance

c. the voltage amplitude across the resistor is

And across the inductor we have

d. the phase angle is calculated as

.

Since it is an R-L circuit, the voltage lead the current.

e. see the attachment.  

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i believe the answer would be:

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