The hubble constant is about 70 km/s/mpc 70 km/s/mpc , which means that a galaxy traveling at 2100 km/s 2100 km/s away from the milky way is about 30 mpc away. messier 77 this spiral galaxy is traveling away from the milky way at about 1140 km/s 1140 km/s and is about 14 mpc 14 mpc away. what would the velocity of the milky way be as seen from such a galaxy

velocity of the Milky Way be as seen from such a galaxy =V = 2100 Km/s

Accuracy to the Hubble constant is hard to gauge, yet it is for the most part evaluated to be around 65 km/s/Mpc in distance. 1Mpc = 3000000 light years

It implies that one cosmic system having 1 Mpc separation will be moving to another country from us at a speed of 65 km/sec, while another universe having 100 Mpc separation will be subsiding at multiple times this speed.

Explanation:

Edwin Hubble expresses that all worlds become visible to be moving to another country from one another. It implies that the universe was growing because of the movement of cosmic systems from one another. This angle showed up as a redshift of a system's range. This redshift comes into focus to be bigger for black outs, apparently further, universes. Consequently, the more distant a cosmic system, the quicker it is subsiding from

First to answer this question one must know about Redshift and Hubble Law.

Redshift Law:

This is related to astronomers. Redshift can be understood by the wavelength of the stretched light. This light is shifted towards the red part of the spectrum. This phenomenon is similar to sound waves.

Hubble Law:

According to this law, “Galaxies are moving from each other with a speed proportional to their distance.” This shows that the universe is expanding.

velocity of the Milky Way is given as

V= H X D   (1)

V = recession velocity

D = distance = 30 Mpc

H = Hubble constant = 70 km/s/Mpc

V = 70 km/s/Mpc x 30 Mpc

velocity of the Milky Way be as seen from such a galaxy =V = 2100 Km/s

thermal energy is the answer