Alex throws a 0.15-kg rubber ball down onto the floor. the ball’s speed just before impact is 6.5 m/s and just after is 3.5 m/s. if the ball is in contact with the floor for 0.050 s, what is the magnitude of the average force applied by the floor on the ball?

F = 30 N  Directed up

Explanation:

We can solve this problem using the momentum and momentum relationship.

      I = ΔP

     I = ∫ F dt

As we are asked for the average force, that leaves the integral, giving

    I = F t

    F t = m - m v₀

    F = m (-v₀) / t

Note that, if you define the upward positive direction, the initial velocity is negative

Let's calculate

     F = 0.15 (3.5 - (-6.5)) / 0.050

     F = 30 N

Directed up

answer: 0.20

explanation: this can only be the answew because all the other measuremnets are not close

a displacement distance is size of displ