Physics, 26.12.2019 03:31 loganharper992
The turnover number for an enzyme is known to be 500 min-1 . a mutant of the enzyme was made that resulted in the destabilization of the es complex of 1 kcal/mole, and a destabilization of transition state (es‡ ) of 2.5 kcal/mol. calculate the kcat of the mutant enzyme (assuming a temperature of 27°c). kcat = (kbt/h).e-(δg‡/rt) t = temperature in kelvin kb = 3.297 ×10−24 cal/k h = 1.583 x 10-34 cal. s r = 2 cal/k. mol
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The turnover number for an enzyme is known to be 500 min-1 . a mutant of the enzyme was made that re...
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