An object 5.ocm in the length is placed at a distance of 20cm in front of convex mirror
radius of curvature 30 cm find the position, nature and size of image.

Position = behind the mirror

Nature = Virtual and Erect

Size = : Diminished

Explanation:

Sign convention-Distance measured to the left of pole is negative and to the right of pole is positive.

Object distance = u = -20 cm

Focal length = f = Radius of curvature/2 = 30/2 = 15 cm

We have to use mirror formula to find image distance.

Since the image distance is positive, it is formed behind the mirror or a virtual image is formed.

Magnification =

Height of the object = 5 cm

Height of the image =

Since the height of the image is positive and less than the size of object,it is erect and diminished.

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