Along jumper leaves the ground at an angle of 22.5 ∘ measured from the horizontal, and at a speed of 11.0 m/s. how far does he jump? hint: first determine how long he is in the air, which is twice the time it takes him to reach his maximum height.

Explanation:

Consider the vertical motion of long jumper

We have equation of motion v = u + at

     Initial velocity, u = 11 sin 22.5 = 4.21 m/s

     Final velocity, v =  0 m/s    

     Acceleration, a = -9.81 m/s²

     Substituting

                      v = u + at  

                      0 = 4.21 + -9.81 x t

                      t = 0.43 s

So the Long jumper is in air for 0.43 seconds.

Now consider the vertical motion of long jumper

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 11 cos 22.5 = 10.16 m/s

        Acceleration, a = 0 m/s²  

        Time, t = 0.43 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 10.16 x 0.43 + 0.5 x 0 x 0.43²

                      s = 4.37 m

He jumps 4.37 m

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )