Consider two point charges located on the x axis: one charge, q1 = -11.5nc , is located at x1 = -1.685m ; the second charge, q2 = 40.0nc , is at the origin (x=0.).what is the net force exerted by these two charges on a third charge q3 = 55.0nc placed between q1 and q2 at x3 = -1.195m ?

Explanation:

q1 = -11.5nC   , x1 = -1.685m

q2 = 40.0nC ,  x=0.0000m

q3 = 55.0nC  , x3 = -1.195m

Force on charge 3 due to charge 1 (attractive)

By applying coulomb law

r = 1.685-1.195

r =  0.49 m

Force on charge 3 due to charge 2 (repulsive)

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step-by-step explanation: