Two pellets, with charges q1 = 22 μc and q2 = 11 μc (1 μc = 10-6 c or 1 microcoulomb = 0.1 coulombs), are located 0.52 m apart.

(a) what is the electric force between them? in n(b) what mass object would experience this same force in the earth's gravitational field? in kg

8.0 N

0.82 kg

Explanation:

Given data

q₁ = 22 × 10⁻⁶ c

q₂ = 11 × 10⁻⁶ c

distance (r): 0.52 m

We can find the electrical force between these charges using he Coulomb's law.

If the same force were experienced due to the gravitational field, we could find the value of mass associated with it using Newton's second law of motion.

F = m . g

8.0 N = m . 9.8 m/s²

m = 0.82 kg

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//