An outfielder throws a 1.1 kg baseball at a speed of 62 m/s and an initial angle of 12.3 ◦ . what is the kinetic energy of the ball at the highest point of its motion? answer in units of j.

= 2,018.3 J

Explanation:

mass (m) = 1.1 kg

velocity (v) = 62 m/s

initial angle(θ) = 12.3°

kinetic energy =

where

      v = Vx + Vy  (horizontal component + vertical component)

      at the maximum height, velocity is 0, so Vy = 0 and v= Vx

      v = Vx = v.cosθ

      v = 62 x cos 12.3 = 60.6 m/s

therefore kinetic energy = =

= 2,018.3 J

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