Physics, 28.12.2019 06:31 Tripz3005

Acork has weight mg and density 25% of water’s density. a string is tied around the cork and attached to the bottom of a water-filled container. the cork is totally immersed. express the tension in the string in terms of the cork weight mg.

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Answer from: dillon100097

Explanation:

Given

Density of Cork $\rho _c=0.25\rho _{water}$

Considering V be the volume of Cork

Buoyant Force will be acting Upward and Weight is acting Downward along with T

Since density of water is more than cork therefore Cork will try to escape out of water but due to tension it will not

we can write as

$\rho _{water}Vg-\rho _Cvg-T=0$

where T=tension

Thus Tension T is

$T=Vg(\rho _{water}-\rho _c)$

Taking $\rho _c$ common

$T=\rho _cVg(\frac{\rho _{water}}{\rho _c}-1)$

$T=mg(\frac{\rho _{water}}{\rho _c}-1)$

T=mg(4-1)

T=3mg

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

Answer from: Quest

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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Acork has weight mg and density 25% of water’s density. a string is tied around the cork and attache...

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