Aconductor of length 2m carrying a 1.5a current experiences a force of 2.2 n. what is the magnitude of the magnetic field that acts perpendicular to the flow of current in the conductor?

Magnetic field, B = 0.74 T

Explanation:

It is given that,

Length of the conductor, L = 2 m

Current in conductor, I = 1.5 A

Magnetic force, F = 2.2 N

We need to find the magnitude of the magnetic field that acts perpendicular to the flow of current in the conductor. It is given by :

B = 0.74 T

So, the magnitude of magnetic field will be 0.74 T. Hence, this is the required solution.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

this is poiselle's equation from fluid mechanic in physics. mech eng