Determine the mass of ar in 1.00 liter of a gas mixture at 25oc which contains 0.300 atm of ne and has a total pressure of 4.00 atm.

The mass of Ar is 36.91g

Explanation:

The gas mixture consist of Neon(Ne) and Argon(Ar)

Partial pressure of Ar = total pressure of mixture - partial pressure = 4 - 0.3 = 3.7 atm

Mole fraction of Ar = partial pressure of Ar ÷ total pressure of mixture = 3.7/4 = 0.925

Mass of Ar = 0.925 × molecular weight of Ar = 0.925 × 39.9 = 36.91g

the answer would be c. motion and direction

i hope this : )

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.