Asingle conservative force f(x) = b x + a acts on a 4.37 kg particle, where x is in meters, b = 6.09 n/m and a = 5.96 n. as the particle moves along the x axis from x1 = 0.652 m to x2 = 5.1 m, calculate the work done by this force. answer in units of j.

104.41 J

Explanation:

Given

Force acting

mass of particle

Work done is given by

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