Aball of mass 5 kg attached to a string is swung in a horizontal circle of radius 0.5 m. if the tension in the string is 10 n, the work done by the tension in one revolution is j.

0 J

Explanation:

given,

mass of the ball = 5 kg

radius of the horizontal circle = 0.5 m

tension in the string = 10 N

Work done = ?

Work done by the tension in the circular path will be equal to zero.

This is because body moves in circular path, the centripetal force act along the radius of the circle and motion is right angle to the tension on the string.

so, work done = F s cos θ

     θ = 90°,

work done = F s cos 90°        ∵ cos 90° = 0

Work done = 0 J

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr